the CREATE DATABASE statement is used to create a database
---------------------------------------------------------------------
CREATE DATABASE database_name
EXAMPLE
create database student
------------
create table employee
(
ecode char(10),
ename varchar(30),
city char(20),
salary money,
age int
)
drop table employee
insert into employee values ('e001','manash','kolkata',26000,26)
insert into employee values ('e002','saikat','london',26000,26)
insert into employee values ('e003','plash','bengalore',26000,26)
insert into employee values ('e004','sundip','mumbai',26000,26)
insert into employee values ('e005','sudip','santipur',26000,26)
insert into employee values ('e006','babon','kolkata',26000,26)
insert into employee values ('e007','aniban','london',26000,26)
insert into employee values ('e008','souvik','kolkata',26000,26)
select * from employee
create table loan
(
ecode char(10),
loanamnt money,
loandate datetime,
emi money
)
insert into loan values ('eoo1',80000,4/8/2009,500)
insert into loan values ('eoo2',56200,5/9/2008,400)
insert into loan values ('eoo3',54000,3/8/2009,300)
insert into loan values ('eoo4',98000,2/2/2010,400)
insert into loan values ('eoo5',88000,7/6/2007,350)
insert into loan values ('eoo6',89000,5/5/2006,400)
insert into loan values ('eoo7',88000,4/7/2005,600)
--display the current year
select datepart (year,getdate())as 'current year'
--display current date ,month & year
select datepart ()
---------------------------------------------------------------------
CREATE DATABASE database_name
EXAMPLE
create database student
------------
create table employee
(
ecode char(10),
ename varchar(30),
city char(20),
salary money,
age int
)
drop table employee
insert into employee values ('e001','manash','kolkata',26000,26)
insert into employee values ('e002','saikat','london',26000,26)
insert into employee values ('e003','plash','bengalore',26000,26)
insert into employee values ('e004','sundip','mumbai',26000,26)
insert into employee values ('e005','sudip','santipur',26000,26)
insert into employee values ('e006','babon','kolkata',26000,26)
insert into employee values ('e007','aniban','london',26000,26)
insert into employee values ('e008','souvik','kolkata',26000,26)
select * from employee
create table loan
(
ecode char(10),
loanamnt money,
loandate datetime,
emi money
)
insert into loan values ('eoo1',80000,4/8/2009,500)
insert into loan values ('eoo2',56200,5/9/2008,400)
insert into loan values ('eoo3',54000,3/8/2009,300)
insert into loan values ('eoo4',98000,2/2/2010,400)
insert into loan values ('eoo5',88000,7/6/2007,350)
insert into loan values ('eoo6',89000,5/5/2006,400)
insert into loan values ('eoo7',88000,4/7/2005,600)
--display the current year
select datepart (year,getdate())as 'current year'
--display current date ,month & year
select datepart ()